6(y-2)+2=2(3y+5)

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Solution for 6(y-2)+2=2(3y+5) equation: 



6(y-2)+2=2(3y+5)

We move all terms to the left:

6(y-2)+2-(2(3y+5))=0

We multiply parentheses

6y-(2(3y+5))-12+2=0



We calculate terms in parentheses: -(2(3y+5)), so:

2(3y+5)

We multiply parentheses

6y+10

Back to the equation:

-(6y+10)



We add all the numbers together, and all the variables

6y-(6y+10)-10=0

We get rid of parentheses

6y-6y-10-10=0

We add all the numbers together, and all the variables

-20!=0

There is no solution for this equation

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