6(y-2)+2=2(3y-5)

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Solution for 6(y-2)+2=2(3y-5) equation:


Simplifying
6(y + -2) + 2 = 2(3y + -5)

Reorder the terms:
6(-2 + y) + 2 = 2(3y + -5)
(-2 * 6 + y * 6) + 2 = 2(3y + -5)
(-12 + 6y) + 2 = 2(3y + -5)

Reorder the terms:
-12 + 2 + 6y = 2(3y + -5)

Combine like terms: -12 + 2 = -10
-10 + 6y = 2(3y + -5)

Reorder the terms:
-10 + 6y = 2(-5 + 3y)
-10 + 6y = (-5 * 2 + 3y * 2)
-10 + 6y = (-10 + 6y)

Add '10' to each side of the equation.
-10 + 10 + 6y = -10 + 10 + 6y

Combine like terms: -10 + 10 = 0
0 + 6y = -10 + 10 + 6y
6y = -10 + 10 + 6y

Combine like terms: -10 + 10 = 0
6y = 0 + 6y
6y = 6y

Add '-6y' to each side of the equation.
6y + -6y = 6y + -6y

Combine like terms: 6y + -6y = 0
0 = 6y + -6y

Combine like terms: 6y + -6y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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