6(y-2)-4=-3(-7y+2)-3y

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Solution for 6(y-2)-4=-3(-7y+2)-3y equation: 



6(y-2)-4=-3(-7y+2)-3y

We move all terms to the left:

6(y-2)-4-(-3(-7y+2)-3y)=0

We multiply parentheses

6y-(-3(-7y+2)-3y)-12-4=0



We calculate terms in parentheses: -(-3(-7y+2)-3y), so:

-3(-7y+2)-3y

We add all the numbers together, and all the variables

-3y-3(-7y+2)

We multiply parentheses

-3y+21y-6

We add all the numbers together, and all the variables

18y-6

Back to the equation:

-(18y-6)



We add all the numbers together, and all the variables

6y-(18y-6)-16=0

We get rid of parentheses

6y-18y+6-16=0

We add all the numbers together, and all the variables

-12y-10=0

We move all terms containing y to the left, all other terms to the right

-12y=10

y=10/-12

y=-5/6

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