6(y-2)-4=-3(-7y+2)-3y

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Solution for 6(y-2)-4=-3(-7y+2)-3y equation:



6(y-2)-4=-3(-7y+2)-3y
We move all terms to the left:
6(y-2)-4-(-3(-7y+2)-3y)=0
We multiply parentheses
6y-(-3(-7y+2)-3y)-12-4=0
We calculate terms in parentheses: -(-3(-7y+2)-3y), so:
-3(-7y+2)-3y
We add all the numbers together, and all the variables
-3y-3(-7y+2)
We multiply parentheses
-3y+21y-6
We add all the numbers together, and all the variables
18y-6
Back to the equation:
-(18y-6)
We add all the numbers together, and all the variables
6y-(18y-6)-16=0
We get rid of parentheses
6y-18y+6-16=0
We add all the numbers together, and all the variables
-12y-10=0
We move all terms containing y to the left, all other terms to the right
-12y=10
y=10/-12
y=-5/6

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