6(y-2)-5y=4(y+3)

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Solution for 6(y-2)-5y=4(y+3) equation: 



6(y-2)-5y=4(y+3)

We move all terms to the left:

6(y-2)-5y-(4(y+3))=0

We add all the numbers together, and all the variables

-5y+6(y-2)-(4(y+3))=0

We multiply parentheses

-5y+6y-(4(y+3))-12=0



We calculate terms in parentheses: -(4(y+3)), so:

4(y+3)

We multiply parentheses

4y+12

Back to the equation:

-(4y+12)



We add all the numbers together, and all the variables

y-(4y+12)-12=0

We get rid of parentheses

y-4y-12-12=0

We add all the numbers together, and all the variables

-3y-24=0

We move all terms containing y to the left, all other terms to the right

-3y=24

y=24/-3

y=-8

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