6(y-2)=-3y+42

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Solution for 6(y-2)=-3y+42 equation: 



6(y-2)=-3y+42

We move all terms to the left:

6(y-2)-(-3y+42)=0

We multiply parentheses

6y-(-3y+42)-12=0

We get rid of parentheses

6y+3y-42-12=0

We add all the numbers together, and all the variables

9y-54=0

We move all terms containing y to the left, all other terms to the right

9y=54

y=54/9

y=6

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