6(y-2)=3(y+1)

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Solution for 6(y-2)=3(y+1) equation: 



6(y-2)=3(y+1)

We move all terms to the left:

6(y-2)-(3(y+1))=0

We multiply parentheses

6y-(3(y+1))-12=0



We calculate terms in parentheses: -(3(y+1)), so:

3(y+1)

We multiply parentheses

3y+3

Back to the equation:

-(3y+3)



We get rid of parentheses

6y-3y-3-12=0

We add all the numbers together, and all the variables

3y-15=0

We move all terms containing y to the left, all other terms to the right

3y=15

y=15/3

y=5

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