6(y-2)=3y+3-3(5y-1)

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Solution for 6(y-2)=3y+3-3(5y-1) equation:



6(y-2)=3y+3-3(5y-1)
We move all terms to the left:
6(y-2)-(3y+3-3(5y-1))=0
We multiply parentheses
6y-(3y+3-3(5y-1))-12=0
We calculate terms in parentheses: -(3y+3-3(5y-1)), so:
3y+3-3(5y-1)
determiningTheFunctionDomain 3y-3(5y-1)+3
We multiply parentheses
3y-15y+3+3
We add all the numbers together, and all the variables
-12y+6
Back to the equation:
-(-12y+6)
We get rid of parentheses
6y+12y-6-12=0
We add all the numbers together, and all the variables
18y-18=0
We move all terms containing y to the left, all other terms to the right
18y=18
y=18/18
y=1

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