6(y-3)+(-4)=2(3y+1)-8

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Solution for 6(y-3)+(-4)=2(3y+1)-8 equation: 



6(y-3)+(-4)=2(3y+1)-8

We move all terms to the left:

6(y-3)+(-4)-(2(3y+1)-8)=0

We add all the numbers together, and all the variables

6(y-3)-(2(3y+1)-8)-4=0

We multiply parentheses

6y-(2(3y+1)-8)-18-4=0



We calculate terms in parentheses: -(2(3y+1)-8), so:

2(3y+1)-8

We multiply parentheses

6y+2-8

We add all the numbers together, and all the variables

6y-6

Back to the equation:

-(6y-6)



We add all the numbers together, and all the variables

6y-(6y-6)-22=0

We get rid of parentheses

6y-6y+6-22=0

We add all the numbers together, and all the variables

-16!=0

There is no solution for this equation

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