6(y-3)+10=40

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Solution for 6(y-3)+10=40 equation: 



6(y-3)+10=40

We move all terms to the left:

6(y-3)+10-(40)=0

We add all the numbers together, and all the variables

6(y-3)-30=0

We multiply parentheses

6y-18-30=0

We add all the numbers together, and all the variables

6y-48=0

We move all terms containing y to the left, all other terms to the right

6y=48

y=48/6

y=8

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