6(y-3)+2=20

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Solution for 6(y-3)+2=20 equation: 



6(y-3)+2=20

We move all terms to the left:

6(y-3)+2-(20)=0

We add all the numbers together, and all the variables

6(y-3)-18=0

We multiply parentheses

6y-18-18=0

We add all the numbers together, and all the variables

6y-36=0

We move all terms containing y to the left, all other terms to the right

6y=36

y=36/6

y=6

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