6(y-3)+3(y+4)=21

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Solution for 6(y-3)+3(y+4)=21 equation: 



6(y-3)+3(y+4)=21

We move all terms to the left:

6(y-3)+3(y+4)-(21)=0

We multiply parentheses

6y+3y-18+12-21=0

We add all the numbers together, and all the variables

9y-27=0

We move all terms containing y to the left, all other terms to the right

9y=27

y=27/9

y=3

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