6(y-3)-5(y-8)=48-3(y-2)

Solution for 6(y-3)-5(y-8)=48-3(y-2) equation:

6(y-3)-5(y-8)=48-3(y-2)

We move all terms to the left:

6(y-3)-5(y-8)-(48-3(y-2))=0

We multiply parentheses

6y-5y-(48-3(y-2))-18+40=0


We calculate terms in parentheses: -(48-3(y-2)), so:

48-3(y-2)

determiningTheFunctionDomain
-3(y-2)+48

We multiply parentheses

-3y+6+48

We add all the numbers together, and all the variables

-3y+54

Back to the equation:

-(-3y+54)


We add all the numbers together, and all the variables

y-(-3y+54)+22=0

We get rid of parentheses

y+3y-54+22=0

We add all the numbers together, and all the variables

4y-32=0

We move all terms containing y to the left, all other terms to the right

4y=32

y=32/4

y=8