6(y-3)-8y=28

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Solution for 6(y-3)-8y=28 equation: 



6(y-3)-8y=28

We move all terms to the left:

6(y-3)-8y-(28)=0

We add all the numbers together, and all the variables

-8y+6(y-3)-28=0

We multiply parentheses

-8y+6y-18-28=0

We add all the numbers together, and all the variables

-2y-46=0

We move all terms containing y to the left, all other terms to the right

-2y=46

y=46/-2

y=-23

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