6(y-3)=+3(y+1)=48

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Solution for 6(y-3)=+3(y+1)=48 equation:



6(y-3)=+3(y+1)=48
We move all terms to the left:
6(y-3)-(+3(y+1))=0
We multiply parentheses
6y-(+3(y+1))-18=0
We calculate terms in parentheses: -(+3(y+1)), so:
+3(y+1)
determiningTheFunctionDomain 3(y+1)
We multiply parentheses
3y+3
Back to the equation:
-(3y+3)
We get rid of parentheses
6y-3y-3-18=0
We add all the numbers together, and all the variables
3y-21=0
We move all terms containing y to the left, all other terms to the right
3y=21
y=21/3
y=7

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