6(y-3)=20+2y

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Solution for 6(y-3)=20+2y equation: 



6(y-3)=20+2y

We move all terms to the left:

6(y-3)-(20+2y)=0

We add all the numbers together, and all the variables

6(y-3)-(2y+20)=0

We multiply parentheses

6y-(2y+20)-18=0

We get rid of parentheses

6y-2y-20-18=0

We add all the numbers together, and all the variables

4y-38=0

We move all terms containing y to the left, all other terms to the right

4y=38

y=38/4

y=9+1/2

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