6(y-3)=9y-48

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Solution for 6(y-3)=9y-48 equation: 



6(y-3)=9y-48

We move all terms to the left:

6(y-3)-(9y-48)=0

We multiply parentheses

6y-(9y-48)-18=0

We get rid of parentheses

6y-9y+48-18=0

We add all the numbers together, and all the variables

-3y+30=0

We move all terms containing y to the left, all other terms to the right

-3y=-30

y=-30/-3

y=+10

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