6(y-4)+2(y+1)=18

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Solution for 6(y-4)+2(y+1)=18 equation: 



6(y-4)+2(y+1)=18

We move all terms to the left:

6(y-4)+2(y+1)-(18)=0

We multiply parentheses

6y+2y-24+2-18=0

We add all the numbers together, and all the variables

8y-40=0

We move all terms containing y to the left, all other terms to the right

8y=40

y=40/8

y=5

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