6(y-4)-2=-6(-3y+2)-6y

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Solution for 6(y-4)-2=-6(-3y+2)-6y equation: 



6(y-4)-2=-6(-3y+2)-6y

We move all terms to the left:

6(y-4)-2-(-6(-3y+2)-6y)=0

We multiply parentheses

6y-(-6(-3y+2)-6y)-24-2=0



We calculate terms in parentheses: -(-6(-3y+2)-6y), so:

-6(-3y+2)-6y

We add all the numbers together, and all the variables

-6y-6(-3y+2)

We multiply parentheses

-6y+18y-12

We add all the numbers together, and all the variables

12y-12

Back to the equation:

-(12y-12)



We add all the numbers together, and all the variables

6y-(12y-12)-26=0

We get rid of parentheses

6y-12y+12-26=0

We add all the numbers together, and all the variables

-6y-14=0

We move all terms containing y to the left, all other terms to the right

-6y=14

y=14/-6

y=-2+1/3

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