6(y-4)-6=-5(-5y+4)-5y

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Solution for 6(y-4)-6=-5(-5y+4)-5y equation: 



6(y-4)-6=-5(-5y+4)-5y

We move all terms to the left:

6(y-4)-6-(-5(-5y+4)-5y)=0

We multiply parentheses

6y-(-5(-5y+4)-5y)-24-6=0



We calculate terms in parentheses: -(-5(-5y+4)-5y), so:

-5(-5y+4)-5y

We add all the numbers together, and all the variables

-5y-5(-5y+4)

We multiply parentheses

-5y+25y-20

We add all the numbers together, and all the variables

20y-20

Back to the equation:

-(20y-20)



We add all the numbers together, and all the variables

6y-(20y-20)-30=0

We get rid of parentheses

6y-20y+20-30=0

We add all the numbers together, and all the variables

-14y-10=0

We move all terms containing y to the left, all other terms to the right

-14y=10

y=10/-14

y=-5/7

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