6(y-4)-7=-3(-6y+9)-2y

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Solution for 6(y-4)-7=-3(-6y+9)-2y equation: 



6(y-4)-7=-3(-6y+9)-2y

We move all terms to the left:

6(y-4)-7-(-3(-6y+9)-2y)=0

We multiply parentheses

6y-(-3(-6y+9)-2y)-24-7=0



We calculate terms in parentheses: -(-3(-6y+9)-2y), so:

-3(-6y+9)-2y

We add all the numbers together, and all the variables

-2y-3(-6y+9)

We multiply parentheses

-2y+18y-27

We add all the numbers together, and all the variables

16y-27

Back to the equation:

-(16y-27)



We add all the numbers together, and all the variables

6y-(16y-27)-31=0

We get rid of parentheses

6y-16y+27-31=0

We add all the numbers together, and all the variables

-10y-4=0

We move all terms containing y to the left, all other terms to the right

-10y=4

y=4/-10

y=-2/5

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