6(y-4)-8y=-18

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Solution for 6(y-4)-8y=-18 equation: 



6(y-4)-8y=-18

We move all terms to the left:

6(y-4)-8y-(-18)=0

We add all the numbers together, and all the variables

-8y+6(y-4)+18=0

We multiply parentheses

-8y+6y-24+18=0

We add all the numbers together, and all the variables

-2y-6=0

We move all terms containing y to the left, all other terms to the right

-2y=6

y=6/-2

y=-3

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