6(y-4)-8y=-36

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Solution for 6(y-4)-8y=-36 equation: 



6(y-4)-8y=-36

We move all terms to the left:

6(y-4)-8y-(-36)=0

We add all the numbers together, and all the variables

-8y+6(y-4)+36=0

We multiply parentheses

-8y+6y-24+36=0

We add all the numbers together, and all the variables

-2y+12=0

We move all terms containing y to the left, all other terms to the right

-2y=-12

y=-12/-2

y=+6

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