6(y-4)=5(y+3)

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Solution for 6(y-4)=5(y+3) equation: 



6(y-4)=5(y+3)

We move all terms to the left:

6(y-4)-(5(y+3))=0

We multiply parentheses

6y-(5(y+3))-24=0



We calculate terms in parentheses: -(5(y+3)), so:

5(y+3)

We multiply parentheses

5y+15

Back to the equation:

-(5y+15)



We get rid of parentheses

6y-5y-15-24=0

We add all the numbers together, and all the variables

y-39=0

We move all terms containing y to the left, all other terms to the right

y=39

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