6(y-5)+4(y+3)=32

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Solution for 6(y-5)+4(y+3)=32 equation:


Simplifying
6(y + -5) + 4(y + 3) = 32

Reorder the terms:
6(-5 + y) + 4(y + 3) = 32
(-5 * 6 + y * 6) + 4(y + 3) = 32
(-30 + 6y) + 4(y + 3) = 32

Reorder the terms:
-30 + 6y + 4(3 + y) = 32
-30 + 6y + (3 * 4 + y * 4) = 32
-30 + 6y + (12 + 4y) = 32

Reorder the terms:
-30 + 12 + 6y + 4y = 32

Combine like terms: -30 + 12 = -18
-18 + 6y + 4y = 32

Combine like terms: 6y + 4y = 10y
-18 + 10y = 32

Solving
-18 + 10y = 32

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '18' to each side of the equation.
-18 + 18 + 10y = 32 + 18

Combine like terms: -18 + 18 = 0
0 + 10y = 32 + 18
10y = 32 + 18

Combine like terms: 32 + 18 = 50
10y = 50

Divide each side by '10'.
y = 5

Simplifying
y = 5

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