6(y-9)+37=3(4y+8)-49

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Solution for 6(y-9)+37=3(4y+8)-49 equation: 



6(y-9)+37=3(4y+8)-49

We move all terms to the left:

6(y-9)+37-(3(4y+8)-49)=0

We multiply parentheses

6y-(3(4y+8)-49)-54+37=0



We calculate terms in parentheses: -(3(4y+8)-49), so:

3(4y+8)-49

We multiply parentheses

12y+24-49

We add all the numbers together, and all the variables

12y-25

Back to the equation:

-(12y-25)



We add all the numbers together, and all the variables

6y-(12y-25)-17=0

We get rid of parentheses

6y-12y+25-17=0

We add all the numbers together, and all the variables

-6y+8=0

We move all terms containing y to the left, all other terms to the right

-6y=-8

y=-8/-6

y=1+1/3

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