6(y/3)y+(4/3)y=0

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Solution for 6(y/3)y+(4/3)y=0 equation: 



6(y/3)y+(4/3)y=0



Domain of the equation: 3)y!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

6(+y/3)y+(+4/3)y=0

We multiply parentheses

6y^2+4y^2=0

We add all the numbers together, and all the variables

10y^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{20}=0$

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