6(z+1)=5(z-4)+2

Solution for 6(z+1)=5(z-4)+2 equation:

Simplifying
6(z + 1) = 5(z + -4) + 2

Reorder the terms:
6(1 + z) = 5(z + -4) + 2
(1 * 6 + z * 6) = 5(z + -4) + 2
(6 + 6z) = 5(z + -4) + 2

Reorder the terms:
6 + 6z = 5(-4 + z) + 2
6 + 6z = (-4 * 5 + z * 5) + 2
6 + 6z = (-20 + 5z) + 2

Reorder the terms:
6 + 6z = -20 + 2 + 5z

Combine like terms: -20 + 2 = -18
6 + 6z = -18 + 5z

Solving
6 + 6z = -18 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
6 + 6z + -5z = -18 + 5z + -5z

Combine like terms: 6z + -5z = 1z
6 + 1z = -18 + 5z + -5z

Combine like terms: 5z + -5z = 0
6 + 1z = -18 + 0
6 + 1z = -18

Add '-6' to each side of the equation.
6 + -6 + 1z = -18 + -6

Combine like terms: 6 + -6 = 0
0 + 1z = -18 + -6
1z = -18 + -6

Combine like terms: -18 + -6 = -24
1z = -24

Divide each side by '1'.
z = -24

Simplifying
z = -24