6(z+10)=5-(-6z-55)

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Solution for 6(z+10)=5-(-6z-55) equation: 



6(z+10)=5-(-6z-55)

We move all terms to the left:

6(z+10)-(5-(-6z-55))=0

We multiply parentheses

6z-(5-(-6z-55))+60=0



We calculate terms in parentheses: -(5-(-6z-55)), so:

5-(-6z-55)

determiningTheFunctionDomain
-(-6z-55)+5

We get rid of parentheses

6z+55+5

We add all the numbers together, and all the variables

6z+60

Back to the equation:

-(6z+60)



We get rid of parentheses

6z-6z-60+60=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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