6(z+2)-2(2z+5)=18

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Solution for 6(z+2)-2(2z+5)=18 equation:


Simplifying
6(z + 2) + -2(2z + 5) = 18

Reorder the terms:
6(2 + z) + -2(2z + 5) = 18
(2 * 6 + z * 6) + -2(2z + 5) = 18
(12 + 6z) + -2(2z + 5) = 18

Reorder the terms:
12 + 6z + -2(5 + 2z) = 18
12 + 6z + (5 * -2 + 2z * -2) = 18
12 + 6z + (-10 + -4z) = 18

Reorder the terms:
12 + -10 + 6z + -4z = 18

Combine like terms: 12 + -10 = 2
2 + 6z + -4z = 18

Combine like terms: 6z + -4z = 2z
2 + 2z = 18

Solving
2 + 2z = 18

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 2z = 18 + -2

Combine like terms: 2 + -2 = 0
0 + 2z = 18 + -2
2z = 18 + -2

Combine like terms: 18 + -2 = 16
2z = 16

Divide each side by '2'.
z = 8

Simplifying
z = 8

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