6(z+2)-2(2z+5)=8

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Solution for 6(z+2)-2(2z+5)=8 equation:


Simplifying
6(z + 2) + -2(2z + 5) = 8

Reorder the terms:
6(2 + z) + -2(2z + 5) = 8
(2 * 6 + z * 6) + -2(2z + 5) = 8
(12 + 6z) + -2(2z + 5) = 8

Reorder the terms:
12 + 6z + -2(5 + 2z) = 8
12 + 6z + (5 * -2 + 2z * -2) = 8
12 + 6z + (-10 + -4z) = 8

Reorder the terms:
12 + -10 + 6z + -4z = 8

Combine like terms: 12 + -10 = 2
2 + 6z + -4z = 8

Combine like terms: 6z + -4z = 2z
2 + 2z = 8

Solving
2 + 2z = 8

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 2z = 8 + -2

Combine like terms: 2 + -2 = 0
0 + 2z = 8 + -2
2z = 8 + -2

Combine like terms: 8 + -2 = 6
2z = 6

Divide each side by '2'.
z = 3

Simplifying
z = 3

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