6(z+2)=-36+2

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Solution for 6(z+2)=-36+2 equation: 



6(z+2)=-36+2

We move all terms to the left:

6(z+2)-(-36+2)=0

We add all the numbers together, and all the variables

6(z+2)-(-34)=0

We add all the numbers together, and all the variables

6(z+2)+34=0

We multiply parentheses

6z+12+34=0

We add all the numbers together, and all the variables

6z+46=0

We move all terms containing z to the left, all other terms to the right

6z=-46

z=-46/6

z=-7+2/3

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