6(z+2)=28+2z

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Solution for 6(z+2)=28+2z equation: 


Simplifying
6(z + 2) = 28 + 2z

Reorder the terms:
6(2 + z) = 28 + 2z
(2 * 6 + z * 6) = 28 + 2z
(12 + 6z) = 28 + 2z

Solving
12 + 6z = 28 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
12 + 6z + -2z = 28 + 2z + -2z

Combine like terms: 6z + -2z = 4z
12 + 4z = 28 + 2z + -2z

Combine like terms: 2z + -2z = 0
12 + 4z = 28 + 0
12 + 4z = 28

Add '-12' to each side of the equation.
12 + -12 + 4z = 28 + -12

Combine like terms: 12 + -12 = 0
0 + 4z = 28 + -12
4z = 28 + -12

Combine like terms: 28 + -12 = 16
4z = 16

Divide each side by '4'.
z = 4

Simplifying
z = 4

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