6(z+2)=3(z+1)-18

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Solution for 6(z+2)=3(z+1)-18 equation:


Simplifying
6(z + 2) = 3(z + 1) + -18

Reorder the terms:
6(2 + z) = 3(z + 1) + -18
(2 * 6 + z * 6) = 3(z + 1) + -18
(12 + 6z) = 3(z + 1) + -18

Reorder the terms:
12 + 6z = 3(1 + z) + -18
12 + 6z = (1 * 3 + z * 3) + -18
12 + 6z = (3 + 3z) + -18

Reorder the terms:
12 + 6z = 3 + -18 + 3z

Combine like terms: 3 + -18 = -15
12 + 6z = -15 + 3z

Solving
12 + 6z = -15 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
12 + 6z + -3z = -15 + 3z + -3z

Combine like terms: 6z + -3z = 3z
12 + 3z = -15 + 3z + -3z

Combine like terms: 3z + -3z = 0
12 + 3z = -15 + 0
12 + 3z = -15

Add '-12' to each side of the equation.
12 + -12 + 3z = -15 + -12

Combine like terms: 12 + -12 = 0
0 + 3z = -15 + -12
3z = -15 + -12

Combine like terms: -15 + -12 = -27
3z = -27

Divide each side by '3'.
z = -9

Simplifying
z = -9

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