6(z+2)=4(z+1)-6

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Solution for 6(z+2)=4(z+1)-6 equation:


Simplifying
6(z + 2) = 4(z + 1) + -6

Reorder the terms:
6(2 + z) = 4(z + 1) + -6
(2 * 6 + z * 6) = 4(z + 1) + -6
(12 + 6z) = 4(z + 1) + -6

Reorder the terms:
12 + 6z = 4(1 + z) + -6
12 + 6z = (1 * 4 + z * 4) + -6
12 + 6z = (4 + 4z) + -6

Reorder the terms:
12 + 6z = 4 + -6 + 4z

Combine like terms: 4 + -6 = -2
12 + 6z = -2 + 4z

Solving
12 + 6z = -2 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
12 + 6z + -4z = -2 + 4z + -4z

Combine like terms: 6z + -4z = 2z
12 + 2z = -2 + 4z + -4z

Combine like terms: 4z + -4z = 0
12 + 2z = -2 + 0
12 + 2z = -2

Add '-12' to each side of the equation.
12 + -12 + 2z = -2 + -12

Combine like terms: 12 + -12 = 0
0 + 2z = -2 + -12
2z = -2 + -12

Combine like terms: -2 + -12 = -14
2z = -14

Divide each side by '2'.
z = -7

Simplifying
z = -7

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