6(z+2)=4z+6

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Solution for 6(z+2)=4z+6 equation: 



6(z+2)=4z+6

We move all terms to the left:

6(z+2)-(4z+6)=0

We multiply parentheses

6z-(4z+6)+12=0

We get rid of parentheses

6z-4z-6+12=0

We add all the numbers together, and all the variables

2z+6=0

We move all terms containing z to the left, all other terms to the right

2z=-6

z=-6/2

z=-3

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