6(z+2)=5(z-8)+z

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Solution for 6(z+2)=5(z-8)+z equation: 


Simplifying
6(z + 2) = 5(z + -8) + z

Reorder the terms:
6(2 + z) = 5(z + -8) + z
(2 * 6 + z * 6) = 5(z + -8) + z
(12 + 6z) = 5(z + -8) + z

Reorder the terms:
12 + 6z = 5(-8 + z) + z
12 + 6z = (-8 * 5 + z * 5) + z
12 + 6z = (-40 + 5z) + z

Combine like terms: 5z + z = 6z
12 + 6z = -40 + 6z

Add '-6z' to each side of the equation.
12 + 6z + -6z = -40 + 6z + -6z

Combine like terms: 6z + -6z = 0
12 + 0 = -40 + 6z + -6z
12 = -40 + 6z + -6z

Combine like terms: 6z + -6z = 0
12 = -40 + 0
12 = -40

Solving
12 = -40

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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