6(z+22)=6z+132

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Solution for 6(z+22)=6z+132 equation: 



6(z+22)=6z+132

We move all terms to the left:

6(z+22)-(6z+132)=0

We multiply parentheses

6z-(6z+132)+132=0

We get rid of parentheses

6z-6z-132+132=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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