6(z+3)+3z=36

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Solution for 6(z+3)+3z=36 equation: 



6(z+3)+3z=36

We move all terms to the left:

6(z+3)+3z-(36)=0

We add all the numbers together, and all the variables

3z+6(z+3)-36=0

We multiply parentheses

3z+6z+18-36=0

We add all the numbers together, and all the variables

9z-18=0

We move all terms containing z to the left, all other terms to the right

9z=18

z=18/9

z=2

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