6(z+3)+4(2-z)=5z

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Solution for 6(z+3)+4(2-z)=5z equation: 



6(z+3)+4(2-z)=5z

We move all terms to the left:

6(z+3)+4(2-z)-(5z)=0

We add all the numbers together, and all the variables

6(z+3)+4(-1z+2)-5z=0

We add all the numbers together, and all the variables

-5z+6(z+3)+4(-1z+2)=0

We multiply parentheses

-5z+6z-4z+18+8=0

We add all the numbers together, and all the variables

-3z+26=0

We move all terms containing z to the left, all other terms to the right

-3z=-26

z=-26/-3

z=8+2/3

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