6(z+3)-2z=34

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Solution for 6(z+3)-2z=34 equation: 



6(z+3)-2z=34

We move all terms to the left:

6(z+3)-2z-(34)=0

We add all the numbers together, and all the variables

-2z+6(z+3)-34=0

We multiply parentheses

-2z+6z+18-34=0

We add all the numbers together, and all the variables

4z-16=0

We move all terms containing z to the left, all other terms to the right

4z=16

z=16/4

z=4

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