6(z+3)-5(3z-2)=2(2z-9)

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Solution for 6(z+3)-5(3z-2)=2(2z-9) equation:


6(z+3)-5(3z-2)=2(2z-9)

We simplify the equation to the form, which is simple to understand
6(z+3)-5(3z-2)=2(2z-9)

Reorder the terms in parentheses
+(+6z+18)-5*(3z-2)=2*(2z-9)

Remove unnecessary parentheses
+6z+18-5+*(+3z-2+)=+2+*(+2z-9+)

Reorder the terms in parentheses
+6z+18+(-15z+10)=2*(2z-9)

Remove unnecessary parentheses
+6z+18-15z+10=+2+*(+2z-9+)

Reorder the terms in parentheses
+6z+18-15z+10=+(+4z-18)

Remove unnecessary parentheses
+6z+18-15z+10=+4z-18

We move all terms containing z to the left and all other terms to the right.
+6z-15z-4z=-18-18-10

We simplify left and right side of the equation.
-13z=-46

We divide both sides of the equation by -13 to get z.
z=3.53846153846

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