6(z+3)=30

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Solution for 6(z+3)=30 equation: 



6(z+3)=30

We move all terms to the left:

6(z+3)-(30)=0

We multiply parentheses

6z+18-30=0

We add all the numbers together, and all the variables

6z-12=0

We move all terms containing z to the left, all other terms to the right

6z=12

z=12/6

z=2

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