6(z+3)=42+3z

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Solution for 6(z+3)=42+3z equation: 



6(z+3)=42+3z

We move all terms to the left:

6(z+3)-(42+3z)=0

We add all the numbers together, and all the variables

6(z+3)-(3z+42)=0

We multiply parentheses

6z-(3z+42)+18=0

We get rid of parentheses

6z-3z-42+18=0

We add all the numbers together, and all the variables

3z-24=0

We move all terms containing z to the left, all other terms to the right

3z=24

z=24/3

z=8

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