6(z+3)=5(z-4)+z

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Solution for 6(z+3)=5(z-4)+z equation:


Simplifying
6(z + 3) = 5(z + -4) + z

Reorder the terms:
6(3 + z) = 5(z + -4) + z
(3 * 6 + z * 6) = 5(z + -4) + z
(18 + 6z) = 5(z + -4) + z

Reorder the terms:
18 + 6z = 5(-4 + z) + z
18 + 6z = (-4 * 5 + z * 5) + z
18 + 6z = (-20 + 5z) + z

Combine like terms: 5z + z = 6z
18 + 6z = -20 + 6z

Add '-6z' to each side of the equation.
18 + 6z + -6z = -20 + 6z + -6z

Combine like terms: 6z + -6z = 0
18 + 0 = -20 + 6z + -6z
18 = -20 + 6z + -6z

Combine like terms: 6z + -6z = 0
18 = -20 + 0
18 = -20

Solving
18 = -20

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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