6(z+4)+4z=8(z+2)

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Solution for 6(z+4)+4z=8(z+2) equation: 



6(z+4)+4z=8(z+2)

We move all terms to the left:

6(z+4)+4z-(8(z+2))=0

We add all the numbers together, and all the variables

4z+6(z+4)-(8(z+2))=0

We multiply parentheses

4z+6z-(8(z+2))+24=0



We calculate terms in parentheses: -(8(z+2)), so:

8(z+2)

We multiply parentheses

8z+16

Back to the equation:

-(8z+16)



We add all the numbers together, and all the variables

10z-(8z+16)+24=0

We get rid of parentheses

10z-8z-16+24=0

We add all the numbers together, and all the variables

2z+8=0

We move all terms containing z to the left, all other terms to the right

2z=-8

z=-8/2

z=-4

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