6(z+4)=10z+12

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Solution for 6(z+4)=10z+12 equation: 



6(z+4)=10z+12

We move all terms to the left:

6(z+4)-(10z+12)=0

We multiply parentheses

6z-(10z+12)+24=0

We get rid of parentheses

6z-10z-12+24=0

We add all the numbers together, and all the variables

-4z+12=0

We move all terms containing z to the left, all other terms to the right

-4z=-12

z=-12/-4

z=+3

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