6(z+4)=4(z-3)

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Solution for 6(z+4)=4(z-3) equation: 



6(z+4)=4(z-3)

We move all terms to the left:

6(z+4)-(4(z-3))=0

We multiply parentheses

6z-(4(z-3))+24=0



We calculate terms in parentheses: -(4(z-3)), so:

4(z-3)

We multiply parentheses

4z-12

Back to the equation:

-(4z-12)



We get rid of parentheses

6z-4z+12+24=0

We add all the numbers together, and all the variables

2z+36=0

We move all terms containing z to the left, all other terms to the right

2z=-36

z=-36/2

z=-18

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