6(z+5)=-8(2z-19)

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Solution for 6(z+5)=-8(2z-19) equation: 



6(z+5)=-8(2z-19)

We move all terms to the left:

6(z+5)-(-8(2z-19))=0

We multiply parentheses

6z-(-8(2z-19))+30=0



We calculate terms in parentheses: -(-8(2z-19)), so:

-8(2z-19)

We multiply parentheses

-16z+152

Back to the equation:

-(-16z+152)



We get rid of parentheses

6z+16z-152+30=0

We add all the numbers together, and all the variables

22z-122=0

We move all terms containing z to the left, all other terms to the right

22z=122

z=122/22

z=5+6/11

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