6(z+7)=2(4+z)

Solution for 6(z+7)=2(4+z) equation:

6(z+7)=2(4+z)

We move all terms to the left:

6(z+7)-(2(4+z))=0

We add all the numbers together, and all the variables

6(z+7)-(2(z+4))=0

We multiply parentheses

6z-(2(z+4))+42=0


We calculate terms in parentheses: -(2(z+4)), so:

2(z+4)

We multiply parentheses

2z+8

Back to the equation:

-(2z+8)


We get rid of parentheses

6z-2z-8+42=0

We add all the numbers together, and all the variables

4z+34=0

We move all terms containing z to the left, all other terms to the right

4z=-34

z=-34/4

z=-8+1/2