6(z-1)-(4-2z)=7z

Solution for 6(z-1)-(4-2z)=7z equation:

Simplifying
6(z + -1) + -1(4 + -2z) = 7z

Reorder the terms:
6(-1 + z) + -1(4 + -2z) = 7z
(-1 * 6 + z * 6) + -1(4 + -2z) = 7z
(-6 + 6z) + -1(4 + -2z) = 7z
-6 + 6z + (4 * -1 + -2z * -1) = 7z
-6 + 6z + (-4 + 2z) = 7z

Reorder the terms:
-6 + -4 + 6z + 2z = 7z

Combine like terms: -6 + -4 = -10
-10 + 6z + 2z = 7z

Combine like terms: 6z + 2z = 8z
-10 + 8z = 7z

Solving
-10 + 8z = 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
-10 + 8z + -7z = 7z + -7z

Combine like terms: 8z + -7z = 1z
-10 + 1z = 7z + -7z

Combine like terms: 7z + -7z = 0
-10 + 1z = 0

Add '10' to each side of the equation.
-10 + 10 + 1z = 0 + 10

Combine like terms: -10 + 10 = 0
0 + 1z = 0 + 10
1z = 0 + 10

Combine like terms: 0 + 10 = 10
1z = 10

Divide each side by '1'.
z = 10

Simplifying
z = 10